CheerMath

Grade 9 Quadratic Equations Practice

Solve Quadratics by Factoring

A quadratic equation has an x² in it, and factoring is the fastest way in. You'll write equations in standard form, factor them, and read off both roots — without losing one.

Also known as Class 9 maths — the same topics, whether your school calls it grade, class or year.

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Sample questions

A few samples from this topic — try one, then show the answer.

  1. Connect Factors to Solutions

    How does x2  +  3x   −  40  =  0x^{2} \; + \; 3x\, \; - \; 40 \; = \; 0 factor?
    • (x+5)(x−8)  =  0(x + 5)(x - 8) \; = \; 0
    • (x+40)(x−1)  =  0(x + 40)(x - 1) \; = \; 0
    • (x−5)(x−8)  =  0(x - 5)(x - 8) \; = \; 0
    • (x+8)(x−5)  =  0(x + 8)(x - 5) \; = \; 0
    Show answer
    Answer:
    (x+8)(x−5)  =  0(x + 8)(x - 5) \; = \; 0
  2. Connect Factors to Solutions

    The solutions of x2  +  7x   −  18  =  0x^{2} \; + \; 7x\, \; - \; 18 \; = \; 0 are:
    • x  =  −2x \; = \; -2, x  =  9x \; = \; 9
    • x  =  −18x \; = \; -18, x  =  1x \; = \; 1
    • x  =  −9x \; = \; -9, x  =  2x \; = \; 2
    • x  =  2x \; = \; 2, x  =  9x \; = \; 9
    Show answer
    Answer:
    x  =  −9x \; = \; -9, x  =  2x \; = \; 2
  3. Connect Factors to Solutions

    What are the roots of x2  −  x   =  0x^{2} \; - \; x\, \; = \; 0?enter both roots separated by a comma, e.g.,−3,0or−12,3\quad {\scriptsize\color{gray}{\textrm{enter both roots separated by a comma, e.g.,}\;-3,\;0\;\textrm{or}\;-\frac{1}{2},\;3}}
    Show answer
    Answer:
    0, 1

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A worked example

How does x2  +  3x   −  40  =  0x^{2} \; + \; 3x\, \; - \; 40 \; = \; 0 factor?
  1. We need to factor x2  +  3x   −  40x^{2} \; + \; 3x\, \; - \; 40.
  2. Find two numbers that multiply to -40 and add to 3.(8)×(−5)  =  −40  ✓(8)  +  (−5)  =  3  ✓\\ (8) \times (-5) \; = \; -40 \;\checkmark \\ (8) \; + \; (-5) \; = \; 3 \;\checkmark
  3. The correct factoring is (x+8)(x−5)  =  0  ✓(x + 8)(x - 5) \; = \; 0 \;\checkmark
  4. Why not the other options?(x+5)(x−8)  =  0→\\ (x + 5)(x - 8) \; = \; 0 \toexpanding this does not give x2  +  3x   −  40x^{2} \; + \; 3x\, \; - \; 40 ✘(x+40)(x−1)  =  0→\\ (x + 40)(x - 1) \; = \; 0 \toexpanding this does not give x2  +  3x   −  40x^{2} \; + \; 3x\, \; - \; 40 ✘(x−5)(x−8)  =  0→\\ (x - 5)(x - 8) \; = \; 0 \toexpanding this does not give x2  +  3x   −  40x^{2} \; + \; 3x\, \; - \; 40 ✘

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